Tuesday, February 27, 2007
Completed Section on Binary Rule, T, Substitution Rule
I reordered the logic of the proofs and included the proof that the crystal satisfies the Binary Rule, according to David's comments in the post below. One thing that needs to be decided on is which Binary Rule to prove (regular or rotated?) and then after proving it for one, how to show that it holds for the other. We had a sketch of how to do this in the problem set writeup, but that argument used T^kC stuff (which currently follows my section on the Binary Rule).
Monday, February 26, 2007
Revised Exactly 1 Writeup
Revised notation
- We changed A_n to A_t to free up n so that we can abbreviate N = (2^n)-1.
- We clarified that B_N, D_N, and Q_N are regions of Z^2 and not occupied sets.
- A_N = tau^N A_0 is also equal to A_infinity intersect D_N (since there is no back fill)
- The set of occupied sites in the first quadrant is now A_N^1 (rather than Q_N as we had before)
- We also have some observations about how applying T conserves population and inserts a checkerboard of blank cells
***** There is a slight problem with our notation for A_N^1. The definition of A_N^1 includes sites on the axes. This is okay for the rotated version of Exactly 1 because there are no occupied cells on the axes. However, the axes in the regular orientation are occupied. This means that it is not the case that A_N^1 = (TA_N) intersect Q_N.
The reason I am encountering this problem is that when I list some initial data for a_N and a_N^1 at the beginning of the Exactly 1 writeup, the data for a_N^1 on the regular neighborhood is not quite accurate because the sites on the axes are double counted. In other words, it is not the case that a_N = 4*a_N^1 -3, like it is for the rotated scheme.
An easy fix would be to simply not give initial data for a_N^1 at the beginning of the Exactly 1 writeup, but instead just initial data for a_N (since this is indepedent of whether we are in the rotated or regular neighborhood).
Wednesday, February 21, 2007
Section 5. of outline -- almost done!
I think the approach we are taking in the writeup is:
1) Prove that U(T^(2k)C) = A_infty (not done)
2) Prove that U(T^(2k)C) satisfies the Binary Rule, and hence A_infty satisfies the Binary Rule (done)
3) Prove that the substitution rule satisfies the Binary Rule, and hence produces A_infty (done)
How do we prove item 1)?
I've uploaded my writeup here: PDF, LaTeX. I have done a lot of work on the other sections, so please read over that if you can (or we can scrutinize it in lab sometime).
Monday, February 19, 2007
1 or 3 Rule
Q_N = 2Q_(N-1) + 8r_(N-2) + correction
By recognizing that by population count that r_N = Q_N (The alternating boundary acts as a row of zeros since the rule is 1 or 3, thus the growth of the r_N's is identical to q_N's on the NE half, and shifted by (-1,-1) on the SW half.) and finding correction through Excel we get
Q_N = 2Q_(N-1) + 8Q_(N-2) - 6
Upon examination the cells which are repeated are at locations:
(2^(N-1), 2^(N-1)) twice,
(2^(N-2), 2^(N-1)+2^(N-2)),
(2^(N-1)+2^(N-2), 2^(N-2)),
(2^(N-2)+1, 2^(N-1)+2^(N-2)-1),
(2^(N-1)+2^(N-2)-1, 2^(N-2)+1),
By subtracting by Q_(N-1) to remove the constant
Q_N = 3Q_(N-1) + 6Q_(N-2) - 8Q_(N-3)
which gives us the characteristic polynomial
x^3 - 3x^2 - 6x + 8 = 0
with roots 4, 1, -2. Thus:
Q_N = c_1*4^n + c_2*(-2)^n + c_3
Fitting this to data for Q_3, Q_4, Q_5, we get
Q_N = (4^n+2)/3.
Since the whole box B_N = 4Q_N - 3 (the origin is counted 3 times too many), B_N = 4/3*4^n - 1/3. Since this is the rotated version, it follows that the density of the 13 rule is 2/3.
Friday, February 16, 2007
Undergraduate Symposium
Follow this link for more info.
Wednesday, February 14, 2007
Exactly 1 Finished Writeup
Edits to "Notation" document
2. Last line: q_n should be q_N, since this is at dyadic times. I also added the definition for b_N.
3. I think the "box neighborhood" and "diamond neighborhood" aren't really neighborhoods in the way that we think of the neighborhood of a point. I think better terms would be dyadic box and dyadic diamond, or something like that. Suggestions?
I've made changes 1. and 2. and uploaded the new notation document here: PDF, LaTeX.
Lab notes 14/2
Notation, Notation, Notation...
Monday, February 12, 2007
Updated Exactly 1 Writeup; Reordered Outline
On the last page of the PDF writeup is the outline, which I have reordered somewhat. I put the proof by induction of the cloning process immediately after the new section on population count formulas. Next comes stuff about the transformation T. (Note that I copy and pasted relevant stuff from last semester into the PDF for these sections, and I still have to re-write these sections.) Let me know if you have suggestions for the outline/order of the writeup.
Sunday, February 11, 2007
Exactly 1 Diamond Writeup
Friday, February 9, 2007
Updated Exactly 1 Diamond Outline
I altered the order somewhat to the (hopefully more logical) following: transformation T,
cloning process, proving density = 2/3 two ways (cloning process, transformation T), the Binary Rule, and the Substution rule.
Thursday, February 8, 2007
Formulas for the population counts of diamond rules
Wednesday, February 7, 2007
Exactly 1 Diamond Rule
Fortunately, we have a rough draft of each of the items I mention. The first step I'd like to do, however, is to get your input on what to include and what organization to use (order of items, depth into which I write about each item, etc.). Then the next step would be to polish and improve the rough drafts of each item.
Tuesday, February 6, 2007
174
Saturday, February 3, 2007
A New Kind of Science
The only other remotely close rule he describes is the "3 or 5" box rule (not counting self) (code = 175850) on page 177, the pattern of which he asserts has "seemingly random irregularities, at least on a small scale" but on a larger scale it follows a "rather smooth curve."